Trigonometry

Trigonometry originates from the study of triangles, particularly, the right angled ones.

Pythagoras Theorem

Pythagoras states that the expression is always be true for any three sides of a right angle triangle, where c is the hypothenuse.

a2+b2=c2

Trigonometry

sin⁡x=opphypcos⁡x=adjhyptan⁡x=oppadj

Trigonometric Identities

sin2⁡(x)+cos2⁡(x)=11+cot2⁡(x)=csc2⁡(x)tan2⁡(x)+1=sec2⁡(x)

We obtained the second expression by dividing the first expression throughout by sin2⁡(x) and the third by dividing the first expression by cos2⁡(x)

Sine rule

sin⁡aA=sin⁡bB=sin⁡cC

Cos rule

c2=a2+b2−2abcos⁡C

let sin⁡ωt have a wavelength of λ

sin⁡(ωt)

The relationship between ω and λ is.

λω=2π

thus

ω=2πf

Double angle formula

sin⁡(a±b)=sin⁡acos⁡b±sin⁡bcos⁡acos⁡(a±b)=cos⁡acos⁡b∓sin⁡asin⁡btan⁡(a±b)=tan⁡a±tan⁡b1∓tan⁡atan⁡b

Harmonic Addition Theorem

Express Rsin⁡(θ+a) as Acos⁡θ+Bsin⁡θ .

Rsin⁡(θ+a)=R(sin⁡θcos⁡a+sin⁡acos⁡θ)=Rcos⁡asin⁡θ+Rsin⁡acos⁡θ

Thus

A=Rsin⁡aB=Rcos⁡a

Reverse Factor Formulae

2sin⁡Acos⁡B=sin⁡(A+B)+sin⁡(A−B)2cos⁡Asin⁡B=sin⁡(A+B)−sin⁡(A−B)2cos⁡Acos⁡B=cos⁡(A+B)+cos⁡(A−B)−2sin⁡Asin⁡B=cos⁡(A+B)−cos⁡(A−B)

Additional Insights (Very useful)

Let us see the properties of these trigo identities.
This section aims to help us find a shortcut to solving questions like: Use Compound angle formula to prove that cos⁡19π12=6−24 etc...

let us define n as

n=k×a+R

where R is the remainder. And k,a,R,n∈Z.
Look at Proof for Symmetries in Trigo Identities. We thus get.

sin⁡(naπ)=(−1)ksin⁡(Raπ)=(−1)ksin⁡(a−Raπ)cos⁡(na)=(−1)kcos⁡(Raπ)=(−1)k+1cos⁡(a−Raπ)

Joshua's approximation method. Estimating cos sin tan without using their respective functions on a calculator

Suppose we want to find the value of

cos⁡(195)

Using the approximation that π≈227. And reducing it using the Proof for Symmetries in Trigo Identities formulas

cos⁡(195)=cos⁡(195722π)=cos⁡(133110π)=(−1)1cos⁡(23110π)

Next, having reduced θ<π2. using the Maclaurin Series expansion for cos up to the x4 term.

−cos⁡(23110π)≈−(1−(23110π)22+(23110π)44!)

We see that

−(1−(23110π)22+(23110π)44!)=−0.792012968067

and using a calculator

cos⁡(195)=−0.790967711914

Comparing the two solution, my method is accurate up to 2dp with an error of 0.001 :)

cos⁡(195)−−(1−(23110π)22+(23110π)44!)=0.001045256153