This section concerns itself with finding the integral of a Gaussian Distribution
Find .
Proof
Lets consider adding another dimension.
where . Let be the radius of the circle. Thus all points a distance from the origin on would have the same value. We can graph out the function against and
We can find the volume under by summing the area under the red line (points of equidistant from the origin) for all values . Unroll the area under the red line to form a rectangle, with length and height , integrate with respect to .
We can express the volume as a double integral as below, where the inner integral integrates in the axis, keeping as a constant. I like to think of the integral as infinitely slicing along the axis and finding the area bounded by in each slice, expressing it as some value. Next the outer integral sums up all these areas by integrating in the direction, thus obtaining the volume under .